"diode" mod for piccoz
Posted: Sat Jun 09, 2007 5:21 pm
There is a small diode on the piccoz PCB that is put there to protect all the noobs from blowing their lipo if one was to plug the charger wire in the wrong way.
Diodes are used for many things in electronics, the simplest is their ability to only allow current to travel in one direction.
For you 'tronic deprived fellas, what this means is that for example, if you had a simple light builb (from a torch) and a battery, connecting the battery either way to the lightbuilt will result in it lighting up. Either way. This is because the lightbulb can except current in either direction.
Now if we put a diode in between the battery and the light, the light will still work, but only when the battery is connected in a certain polarity.
It's not rocket science, just like a one way valve on a LPG bottle you use for the bbq. t only allows the gas to travel in one direction, out of the bottle.
Now, all that shit over.................
The thing is this. Diodes take away approx 0.6V of voltage from the current source they are protecting against.
Eg: from above's example. 1.5V AAA powers up a light. Therefore the voltage at the light is 1.5V. Now if a diode is in between them, the voltage at the light is now (approx) 1.5-0.6 = 0.9V. The light is now "protected" against reverse polarity but at the cost of a 0.6V reduction in voltage.
So what does this mean to the piccoz? .............. here's a SIMPLe picture....

It is a simple picture, shit is omitted for simplicity.....
You can see that the PCB and battery are protected from reverse polarity here. Once the batt is charged, the PCB gets the full voltage from the battery since there is nothing in the way. The diode is used only for charging polarity protection.
Now, why am I writing all this..................
Here's the killa.
Looking at this circuit from the point of the charger, the charger doesn't "see" the battery natively, if only "sees" it through the diode. This is where the 0.6V drop comes into (very important) play.
Some of you may not know, but lipo charging is based on CC then CV. This means a constanc current to a certain voltage level then it goes to a constant voltage mode. I won't go into all this now, but I just wanted to highlight it.
As many of you know, lipos are charged effectively to 4.2V a cell. They run at 3.7V and all is good.
Ahhh, but wait. This 4.2V is to do with the voltage that the charger sees.
Now add the diode.
This is what happens.
1) plug charger in, process starts.
2) charger monitors battery level.
3) the level charger sees is actually (battery voltage) - (didoe).
4) eg: batt is charging and hits 3.6V, charger sees 4.2V (ie: 3.6 +0.6)
5) charging cycle finishes since charge reakons batt is as 4.2V.
Get my drift. The lipo is constantly UNDERCHARGED!
I tested this on my hobby charger. Connecting my ICE to the plug that goes into the picco, I set it to charge for 1S at 100mAh. (yes it's 2C but that's ok, won't blow the lipo up, will reduce it's lifespan, that's OK! lol...)
I only get approx 17mA into a 50mAh batt.,....
No, I removed the batt from the picco altogether and charged it directly connected to the ICE.
Now I get about 40mAh into it.....
Lesson learnt......
Bottom line, remove the diode out of the equation and you WILL get ore charge into the battery AND a longer runtime because of it....
I will post pics later. (8am here, bubs ain't woken yet......)
I'm yet to test this with the picco charger itself. But I'm confident I'm on the right track.....
Here's a pic of the diode in question. The plan is to remove it and just short the 2 pads. You now no longer have reverse polarity protection. But we're not noobs so it's OK!
.

ph2t.
Diodes are used for many things in electronics, the simplest is their ability to only allow current to travel in one direction.
For you 'tronic deprived fellas, what this means is that for example, if you had a simple light builb (from a torch) and a battery, connecting the battery either way to the lightbuilt will result in it lighting up. Either way. This is because the lightbulb can except current in either direction.
Now if we put a diode in between the battery and the light, the light will still work, but only when the battery is connected in a certain polarity.
It's not rocket science, just like a one way valve on a LPG bottle you use for the bbq. t only allows the gas to travel in one direction, out of the bottle.
Now, all that shit over.................

The thing is this. Diodes take away approx 0.6V of voltage from the current source they are protecting against.
Eg: from above's example. 1.5V AAA powers up a light. Therefore the voltage at the light is 1.5V. Now if a diode is in between them, the voltage at the light is now (approx) 1.5-0.6 = 0.9V. The light is now "protected" against reverse polarity but at the cost of a 0.6V reduction in voltage.
So what does this mean to the piccoz? .............. here's a SIMPLe picture....
It is a simple picture, shit is omitted for simplicity.....
You can see that the PCB and battery are protected from reverse polarity here. Once the batt is charged, the PCB gets the full voltage from the battery since there is nothing in the way. The diode is used only for charging polarity protection.
Now, why am I writing all this..................

Here's the killa.
Looking at this circuit from the point of the charger, the charger doesn't "see" the battery natively, if only "sees" it through the diode. This is where the 0.6V drop comes into (very important) play.
Some of you may not know, but lipo charging is based on CC then CV. This means a constanc current to a certain voltage level then it goes to a constant voltage mode. I won't go into all this now, but I just wanted to highlight it.
As many of you know, lipos are charged effectively to 4.2V a cell. They run at 3.7V and all is good.
Ahhh, but wait. This 4.2V is to do with the voltage that the charger sees.
Now add the diode.

This is what happens.
1) plug charger in, process starts.
2) charger monitors battery level.
3) the level charger sees is actually (battery voltage) - (didoe).
4) eg: batt is charging and hits 3.6V, charger sees 4.2V (ie: 3.6 +0.6)
5) charging cycle finishes since charge reakons batt is as 4.2V.
Get my drift. The lipo is constantly UNDERCHARGED!
I tested this on my hobby charger. Connecting my ICE to the plug that goes into the picco, I set it to charge for 1S at 100mAh. (yes it's 2C but that's ok, won't blow the lipo up, will reduce it's lifespan, that's OK! lol...)
I only get approx 17mA into a 50mAh batt.,....

No, I removed the batt from the picco altogether and charged it directly connected to the ICE.
Now I get about 40mAh into it.....
Lesson learnt......
Bottom line, remove the diode out of the equation and you WILL get ore charge into the battery AND a longer runtime because of it....
I will post pics later. (8am here, bubs ain't woken yet......)
I'm yet to test this with the picco charger itself. But I'm confident I'm on the right track.....
Here's a pic of the diode in question. The plan is to remove it and just short the 2 pads. You now no longer have reverse polarity protection. But we're not noobs so it's OK!

ph2t.